Which of the following pairs differ in geomet | vedclass

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(A) $1$. $[Ni(CO)_4]$: $Ni(0)$ is $3d^8 4s^2$. $CO$ is a strong field ligand,causing pairing. Hybridization is $sp^3$,geometry is tetrahedral,and it i

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$[Ni(CO)_4]$ & $[Ni(CN)_4]^{2-}$

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(A) $1$. $[Ni(CO)_4]$: $Ni(0)$ is $3d^8 4s^2$. $CO$ is a strong field ligand,causing pairing. Hybridization is $sp^3$,geometry is tetrahedral,and it is diamagnetic $(n=0)$.$2$. $[Ni(CN)_4]^{2-}$: $Ni(II)$ is $3d^8$. $CN^-$ is a strong field ligand. Hybridization is $dsp^2$,geometry is square planar,and it is diamagnetic $(n=0)$.$3$. Since both are diamagnetic but have different geometries (tetrahedral vs square planar),option $A$ is correct.

List-$I$	List-$II$
$A$. $[MnBr_4]^{2-}$	$I$. $d^2sp^3$ and diamagnetic
$B$. $[FeF_6]^{3-}$	$II$. $sp^3d^2$ and paramagnetic
$C$. $[Co(C_2O_4)_3]^{3-}$	$III$. $sp^3$ and diamagnetic
$D$. $[Ni(CO)_4]$	$IV$. $sp^3$ and paramagnetic

Which of the following pairs differ in geometry but resemble in magnetic behavior?

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